t^2-(t^2/4)=0

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Solution for t^2-(t^2/4)=0 equation: 



t^2-(t^2/4)=0

We get rid of parentheses

t^2-t^2/4=0

We multiply all the terms by the denominator


-t^2+t^2*4=0

We add all the numbers together, and all the variables

-1t^2+t^2*4=0

Wy multiply elements

-1t^2+4t^2=0

We add all the numbers together, and all the variables

3t^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{6}=0$

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